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Higher arithmetic

George Roberts Perkins
4.9/5 (29795 ratings)
Description:This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1851 ...5 200+ 25 1600+ 200 45a=1600+ 400+ 25 40+ 5 8000+2000+125 64000+16000+1000 453 = 64000 + 24000 + 3000+125 Now, to reverse this process, that is, to extract the cube root of 64000 + 24000 + 3000+125, we proceed as I. We find the cube root of 64000 to be 40, which we place to the right of the number, in the form of a quotient in division, for the first part of the root sought. We also place it on the left of the number in a column headed 1st Col.; we next multiply it into itself, and place the result in a column headed 2d Col.; this last result, being multiplied by 40, gives 64000, which we subtract from the number, and obtain the remainder 24000 + 3000+125, which we will call the first dividend. II. We obtain the second term of the 1st column by adding the first term to itself; the result being multiplied by this first term, and added to the first term of the 2d column, gives its second term. Again, adding this first term to the second term of the 1st column, we get its third term. III. We seek how many times the second term of the 2d column is contained in the first dividend; or, simply how many times it is contained in its first part, 24000, which gives 5 for the second part of the root. IV. Finally, we add this 5 to the last term of the 1st column, whose result, multiplied by 5, and added to the last term of the 2d column, gives its third term; which, multiplied by 5, gives 27125 = 24000 + 3000+125. 1st Col. 2d Col. Number. Root. 40 1600 64000+24000+3000 +125(40+5. 80 4800 64000 120 5425 24000+3000 +125 = 27125 125 5425x5 = 27125 0 This work can be written in a more condensed form, as follows, where the ciphers upon the right have been omitted. Case I. From the preceding operation, we may draw the following rule for extracting the cube root of a ...We have made it easy for you to find a PDF Ebooks without any digging. And by having access to our ebooks online or by storing it on your computer, you have convenient answers with Higher arithmetic. To get started finding Higher arithmetic, you are right to find our website which has a comprehensive collection of manuals listed.
Our library is the biggest of these that have literally hundreds of thousands of different products represented.
Pages
396
Format
PDF, EPUB & Kindle Edition
Publisher
N/A
Release
2015
ISBN
1231362723

Higher arithmetic

George Roberts Perkins
4.4/5 (1290744 ratings)
Description: This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1851 ...5 200+ 25 1600+ 200 45a=1600+ 400+ 25 40+ 5 8000+2000+125 64000+16000+1000 453 = 64000 + 24000 + 3000+125 Now, to reverse this process, that is, to extract the cube root of 64000 + 24000 + 3000+125, we proceed as I. We find the cube root of 64000 to be 40, which we place to the right of the number, in the form of a quotient in division, for the first part of the root sought. We also place it on the left of the number in a column headed 1st Col.; we next multiply it into itself, and place the result in a column headed 2d Col.; this last result, being multiplied by 40, gives 64000, which we subtract from the number, and obtain the remainder 24000 + 3000+125, which we will call the first dividend. II. We obtain the second term of the 1st column by adding the first term to itself; the result being multiplied by this first term, and added to the first term of the 2d column, gives its second term. Again, adding this first term to the second term of the 1st column, we get its third term. III. We seek how many times the second term of the 2d column is contained in the first dividend; or, simply how many times it is contained in its first part, 24000, which gives 5 for the second part of the root. IV. Finally, we add this 5 to the last term of the 1st column, whose result, multiplied by 5, and added to the last term of the 2d column, gives its third term; which, multiplied by 5, gives 27125 = 24000 + 3000+125. 1st Col. 2d Col. Number. Root. 40 1600 64000+24000+3000 +125(40+5. 80 4800 64000 120 5425 24000+3000 +125 = 27125 125 5425x5 = 27125 0 This work can be written in a more condensed form, as follows, where the ciphers upon the right have been omitted. Case I. From the preceding operation, we may draw the following rule for extracting the cube root of a ...We have made it easy for you to find a PDF Ebooks without any digging. And by having access to our ebooks online or by storing it on your computer, you have convenient answers with Higher arithmetic. To get started finding Higher arithmetic, you are right to find our website which has a comprehensive collection of manuals listed.
Our library is the biggest of these that have literally hundreds of thousands of different products represented.
Pages
396
Format
PDF, EPUB & Kindle Edition
Publisher
N/A
Release
2015
ISBN
1231362723
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